The acceleration due to gravity on the Moon's surface is one-sixth that on Earth. What net force would be required to accelerate a 20-kg object at 6.5 m/s2 horizontally on the moon?
A) 1.3 N
B) 20 N
C) 33 N
D) 120 N
E) 130 N
To find the net force required to accelerate an object horizontally on the Moon, we need to use Newton's second law of motion, which states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration:
Net force = mass × acceleration
In this case, the given mass is 20 kg and the given acceleration is 6.5 m/s². However, we also need to account for the fact that the acceleration due to gravity on the Moon is one-sixth that on Earth.
So, first we need to find the actual acceleration due to gravity on the Moon:
Acceleration on the Moon = (1/6) × Acceleration on Earth
Acceleration on the Moon = (1/6) × 9.8 m/s² (approximate value of the acceleration due to gravity on Earth)
Acceleration on the Moon = 1.6333... m/s² (rounded to 4 decimal places)
Now that we have the actual acceleration on the Moon, we can plug it into our equation:
Net force = mass × acceleration
Net force = 20 kg × 1.6333... m/s²
Net force ≈ 32.67 N
Rounding to the nearest whole number, we find that the net force required to accelerate a 20 kg object at 6.5 m/s² horizontally on the Moon is approximately 33 N.
So, the correct answer is C) 33 N.
To find the net force required to accelerate a 20-kg object at 6.5 m/s^2 horizontally on the Moon, we can use Newton's second law of motion:
Force = mass * acceleration
Given:
Mass = 20 kg
Acceleration = 6.5 m/s^2 (horizontally)
Since the acceleration due to gravity on the Moon is one-sixth that on Earth, the net force required to achieve the given acceleration would also be one-sixth the force required on Earth.
So, we can find the net force required on the Moon by multiplying the force required on Earth by one-sixth.
Force on Earth = mass * acceleration
Force on Earth = 20 kg * 6.5 m/s^2
Force on Earth = 130 N
Net force required on the Moon = (1/6) * Force on Earth
Net force required on the Moon = (1/6) * 130 N
Net force required on the Moon = 21.67 N
Rounding to the nearest whole number, the net force required to accelerate a 20-kg object at 6.5 m/s^2 horizontally on the Moon is approximately 22 N.
Therefore, the correct answer is C) 33 N.