how many grams of Fe2O3 are formed when 16.7g of Fe reacts completely with oxygen?
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Write and balance the equation.
4Fe + 3O2 ==> 2Fe2O3
Convert 16.7 g Fe to moles. moles = grams/molar mass
Using the coefficients in the balanced equation, convert moles Fe to moles Fe2O3.
Finally, convert moles Fe2O3 to grams. g = moles x molar mass.
To determine the number of grams of Fe2O3 formed, we need to use the balanced chemical equation for the reaction between Fe and oxygen.
The balanced chemical equation is:
4 Fe + 3 O2 -> 2 Fe2O3
From the equation, we can see that 4 moles of Fe react with 3 moles of O2 to produce 2 moles of Fe2O3.
To calculate the number of moles of Fe that react, we divide the given mass of Fe by its molar mass. The molar mass of Fe is 55.85 g/mol.
Number of moles of Fe = Mass of Fe / Molar mass of Fe
Number of moles of Fe = 16.7 g / 55.85 g/mol
Number of moles of Fe ≈ 0.2983 mol (rounded to four decimal places)
Using the mole ratio from the balanced equation, we can determine the number of moles of Fe2O3 formed.
Number of moles of Fe2O3 = (2/4) * Number of moles of Fe
Number of moles of Fe2O3 = (2/4) * 0.2983 mol
Number of moles of Fe2O3 = 0.1491 mol
Finally, we can calculate the mass of Fe2O3 by multiplying the number of moles by its molar mass. The molar mass of Fe2O3 is 159.69 g/mol.
Mass of Fe2O3 = Number of moles of Fe2O3 * Molar mass of Fe2O3
Mass of Fe2O3 = 0.1491 mol * 159.69 g/mol
Mass of Fe2O3 ≈ 23.79 g (rounded to two decimal places)
Therefore, approximately 23.79 grams of Fe2O3 are formed when 16.7 grams of Fe reacts completely with oxygen.
To determine the number of grams of Fe2O3 formed when 16.7g of Fe reacts completely with oxygen, we need to first write a balanced chemical equation for the reaction.
The balanced equation for the reaction between iron (Fe) and oxygen (O2) is:
4Fe + 3O2 -> 2Fe2O3
According to the balanced equation, 4 moles of Fe react with 3 moles of O2 to form 2 moles of Fe2O3.
To find the number of moles of iron (Fe) in 16.7g of Fe, we need to use its molar mass. The molar mass of iron (Fe) is approximately 55.845g/mol.
Number of moles of Fe = Mass of Fe / Molar mass of Fe
Number of moles of Fe = 16.7g / 55.845g/mol
Now, we can use the mole ratio from the balanced equation to determine the number of moles of Fe2O3 formed.
Number of moles of Fe2O3 = (2/4) * Number of moles of Fe
Number of moles of Fe2O3 = (2/4) * (16.7g / 55.845g/mol)
Finally, to find the mass of Fe2O3 formed, we can multiply the number of moles of Fe2O3 by its molar mass. The molar mass of Fe2O3 is approximately 159.688g/mol.
Mass of Fe2O3 = Number of moles of Fe2O3 * Molar mass of Fe2O3
Now you can substitute the values into the equation and calculate the mass of Fe2O3.