Vinyl chloride (H2C=CHCl), the starting material from which PVC polymer is made, has a Henry's-law constant of 0.091mol/(L.atm) at 25 C. What is the solubility of vinyl chloride in water (in mol/L) at 25C and a partial pressure of 0.90 atm? Thank you in advance
I think you want to use C = pk
http://en.wikipedia.org/wiki/Henry%27s_law
Consider the hypothetical reaction below. If the initial pressure of A was 2.58 atm, what would be the partial pressure of C (in atm) at equilibrium? KP = 13.6 at 298 K
2 A <==> B + C
Vinyl chloride (H2C=CHCl), the starting material from which PVC polymer is made, has a Henry's-law constant of 0.091mol/(L⋅atm) at 25 ∘C.
To find the solubility of vinyl chloride (H2C=CHCl) in water at 25°C and a partial pressure of 0.90 atm, we can use Henry's Law. Henry's Law states that the solubility of a gas in a liquid is directly proportional to the partial pressure of the gas above the liquid.
The formula for Henry's Law is:
C = k * P
Where:
C is the molar concentration (solubility) of the gas in the liquid (in mol/L),
k is the Henry's Law constant specific to the gas and liquid (in mol/(L.atm)),
P is the partial pressure of the gas above the liquid (in atm).
Given:
Henry's Law constant (k) for vinyl chloride is 0.091 mol/(L.atm)
Partial pressure (P) of vinyl chloride is 0.90 atm.
To find the solubility (C), we substitute the given values into the formula:
C = (0.091 mol/(L.atm)) * (0.90 atm)
C = 0.082 mol/L
Therefore, the solubility of vinyl chloride in water at 25°C and a partial pressure of 0.90 atm is 0.082 mol/L.