EXPLAIN THE CHEMICAL COMPOSITION OF BOTH SIDE OF THE EQUATION BELOW NUMERICALLY WITH INTEGERS
3CaSO4+2ALCL3= 3CaCL2+AL2(SO4)3
To determine the chemical composition of both sides of the given equation numerically, we need to count the number of atoms of each element on the left and right sides of the equation.
Let's break down the equation and count the atoms on each side:
Left side of the equation: 3CaSO4 + 2AlCl3
- Calcium (Ca): There are 3 calcium atoms on the left side.
- Sulfur (S): There are 3 sulfur atoms on the left side.
- Oxygen (O): Each calcium sulfate (CaSO4) molecule contains 4 oxygen atoms. Since there are 3 CaSO4 molecules, the total number of oxygen atoms is 3 × 4 = 12.
- Aluminum (Al): There are 2 aluminum atoms on the left side.
- Chlorine (Cl): Each aluminum chloride (AlCl3) molecule contains 3 chlorine atoms. Since there are 2 AlCl3 molecules, the total number of chlorine atoms is 2 × 3 = 6.
Right side of the equation: 3CaCl2 + Al2(SO4)3
- Calcium (Ca): There are 3 calcium atoms on the right side.
- Sulfur (S): Each aluminum sulfate (Al2(SO4)3) molecule contains 3 sulfur atoms. Since there is 1 Al2(SO4)3 molecule, the total number of sulfur atoms is 1 × 3 = 3.
- Oxygen (O): Each aluminum sulfate (Al2(SO4)3) molecule contains 12 oxygen atoms. Since there is 1 Al2(SO4)3 molecule, the total number of oxygen atoms is 1 × 12 = 12.
- Aluminum (Al): There are 2 aluminum atoms on the right side.
- Chlorine (Cl): Each calcium chloride (CaCl2) molecule contains 2 chlorine atoms. Since there are 3 CaCl2 molecules, the total number of chlorine atoms is 3 × 2 = 6.
Therefore, the numerical chemical composition of the equation is as follows:
Left side: 3CaSO4 + 2AlCl3
- Calcium (Ca): 3
- Sulfur (S): 3
- Oxygen (O): 12
- Aluminum (Al): 2
- Chlorine (Cl): 6
Right side: 3CaCl2 + Al2(SO4)3
- Calcium (Ca): 3
- Sulfur (S): 3
- Oxygen (O): 12
- Aluminum (Al): 2
- Chlorine (Cl): 6
Both sides of the equation have the same number of each element, which confirms that the equation is balanced.