EXPLAIN THE CHEMICAL COMPOSITION OF BOTH SIDE OF THE EQUATION BELOW NUMERICALLY WITH INTERGERS
3CaSO4+2ALCL3= 3CaCL2+AL2(SO4)3
To determine the chemical composition of both sides of the equation numerically, we need to understand the stoichiometry of each compound involved.
Let's break down the equation into its constituent compounds:
Left Side:
- Compound 1: 3CaSO4
- Compound 2: 2AlCl3
Right Side:
- Compound 3: 3CaCl2
- Compound 4: Al2(SO4)3
Now, let's calculate the number of atoms for each element in each compound.
For Compound 1: 3CaSO4
- Calcium (Ca): 3 atoms × 1 = 3 Ca atoms
- Sulfur (S): 3 atoms × 1 = 3 S atoms
- Oxygen (O): 12 atoms × 4 = 48 O atoms
For Compound 2: 2AlCl3
- Aluminum (Al): 2 atoms × 2 = 4 Al atoms
- Chlorine (Cl): 2 atoms × 3 = 6 Cl atoms
For Compound 3: 3CaCl2
- Calcium (Ca): 3 atoms × 1 = 3 Ca atoms
- Chlorine (Cl): 3 atoms × 2 = 6 Cl atoms
For Compound 4: Al2(SO4)3
- Aluminum (Al): 2 atoms × 2 = 4 Al atoms
- Sulfur (S): 3 atoms × 1 = 3 S atoms
- Oxygen (O): 9 atoms × 4 = 36 O atoms
Therefore, the numerical composition of both sides of the equation is as follows:
Left Side:
- 3CaSO4 contains 3 Ca atoms, 3 S atoms, and 48 O atoms.
- 2AlCl3 contains 4 Al atoms and 6 Cl atoms.
Right Side:
- 3CaCl2 contains 3 Ca atoms and 6 Cl atoms.
- Al2(SO4)3 contains 4 Al atoms, 3 S atoms, and 36 O atoms.