a rectangle and triangle have equal areas.the lenght of the rectangle is 12 inches, and its width is 8 inches.if the base of the triangle is 32 inches,what is the length in inches drawn to the base?

a)12
b)16
c)6
d)8
e)9

It's too much trouble to look for it, Jessica, but I think we have done this problem for you in the last couple of days. Perhaps it was another student.

area triangle = area rectangle.
rectangle = 8" x 12" = 98 in2.
area triangle = 96 in2.

area triangle = 1/2*base*height.
96 in2 = 1/2*32*h
solve for h. I gret 6"

Area of the rectangle is length * width. Aread of the triangle is 1/2 base * height.

The length and width are given. Multiply them to find the area. Take that area to the triangle formula. Area = 1/2 base * height. The base is given. The only unknown is the height. That is solved by the equation. If you do the calculations you will get a number that is in the answer list.

i got 6

y r u guys sooo smart! i wish i was!

never dout your self you are smart

To find the length of the triangle drawn to the base, we need to compare the areas of the rectangle and the triangle.

First, let's calculate the area of the rectangle. The formula for the area of a rectangle is length × width. In this case, the length of the rectangle is 12 inches, and the width is 8 inches. Therefore, the area of the rectangle is 12 × 8 = 96 square inches.

Now, since the triangle and the rectangle have equal areas, the area of the triangle must also be 96 square inches.

The formula for the area of a triangle is 1/2 × base × height. We are given that the base of the triangle is 32 inches. So, we can set up the equation: 1/2 × 32 × height = 96.

To solve for height, we divide both sides of the equation by 16 (1/2 × 32 = 16): 16 × height = 96.

Now we can solve for the height (length of the triangle drawn to the base) by dividing 96 by 16: height = 96 ÷ 16 = 6 inches.

Therefore, the length in inches drawn to the base of the triangle is 6 inches.

The correct answer is c) 6.