Could someone help me with this equation?
Use the quadratic formula to solve the equation...
2x^2 - x = -10
Do you know the quadratic formula?
x = [-b (+ or -) [sqroot](b^2 -2ac)] / [2a]
With your equation, think ax^2 + bx + c = 0
If you add 10 to both sides, you now have:
2x^2 - x + 10 = 0
Using ax^2 + bx + c = 0, we know that a=2, b=-1, and c=10
Plug those into your equation!
* By equation, I meant quadratic formula. Sorry for being vague.
** As well, I typed the quadratic formula wrong.
It's:
x = [-b (+ or -) [sqroot](b^2 -4ac)] / [2a]
Thank you!
Of course! I'd be happy to help you with this equation.
To solve the quadratic equation 2x^2 - x = -10 using the quadratic formula, follow these steps:
Step 1: Make sure that the equation is in the standard form, which is ax^2 + bx + c = 0. In this case, the equation is already in standard form.
Step 2: Identify the values of a, b, and c from the equation. In this case, a = 2, b = -1, and c = -10.
Step 3: Substitute the values of a, b, and c into the quadratic formula:
x = (-b ± √(b^2 - 4ac)) / (2a)
Step 4: Simplify the formula by performing the necessary calculations:
x = (-(-1) ± √((-1)^2 - 4(2)(-10))) / (2(2))
x = (1 ± √(1 + 80)) / 4
x = (1 ± √81) / 4
x = (1 ± 9) / 4
Step 5: Solve for both possible values of x:
x1 = (1 + 9) / 4 = 10 / 4 = 2.5
x2 = (1 - 9) / 4 = -8 / 4 = -2
So the solutions to the equation 2x^2 - x = -10 are x = 2.5 and x = -2.
I hope this helps you solve the equation using the quadratic formula! If you have any more questions, feel free to ask.