Find the center (h,k) and radius r of the circle.
(x-2)^2 + (y+3)^2 =16
a)(2,-3) r=16
b)(-3,2) r=4
c)(2,-3) r=4
d)(-3,2) r=16
To find the center (h,k) and the radius r of a circle given its equation in the form (x-h)^2 + (y-k)^2 = r^2, you can compare the given equation to the standard form equation.
In this case, the given equation is (x-2)^2 + (y+3)^2 = 16. By comparing it to the standard form equation, we can determine the values of h, k, and r.
Comparing the given equation to the standard form equation (x-h)^2 + (y-k)^2 = r^2, we can see that h = 2, k = -3, and r^2 = 16.
Therefore, the center of the circle is (h, k) = (2, -3), and the radius r is the square root of 16, which is 4.
So, the correct answer is:
c) (2, -3) r = 4