what is the weight of a ten foot length of steel pipe? the inside diameter of the pipe is 3/4 of an inch, and the outside diameter i one inch. steel weighs 490lbs. per cubic foot.
area outside = pi (1/2)^2 = pi/4 in^2
area inside = pi (3/8)^2 = 9 pi/64 in ^2
so cross sectional area = .25 pi - .14 pi
= .11 pi in^2
length = 120 in
so
volume = 120*.11 pi = 13.2 pi in^3
then
(13.2 pi in^3) (1 ft^3/12^3 in^3) (490 lb/ft^3
= 3.74 pi lb
=11.76 lb
To determine the weight of a ten-foot length of steel pipe, we need to calculate the volume of the pipe first and then multiply it by the weight density of steel.
First, let's calculate the average diameter of the pipe:
Average diameter = (Inside diameter + Outside diameter) / 2
= (3/4 + 1) / 2
= 1 3/8 inches
Next, let's convert the diameter to feet:
Diameter in feet = 1 3/8 inches / 12 inches per foot
= 1.1667 feet
Now, we can calculate the cross-sectional area of the pipe:
Cross-sectional area = π * (radius)^2
= π * (1.1667 / 2)^2
≈ 1.067 square feet
Since the pipe is ten feet long, the volume of the pipe is:
Volume = cross-sectional area * length
= 1.067 square feet * 10 feet
= 10.67 cubic feet
Finally, we can calculate the weight of the steel pipe:
Weight = volume * weight density
= 10.67 cubic feet * 490 lbs/cubic foot
≈ 5231.3 lbs
Therefore, the weight of a ten-foot length of steel pipe would be approximately 5231.3 lbs.