A 0.750 L bottle of a French Merlot is said to contain 12.5% alcohol by volume. How much of the liquid, in mL, in the bottle is water?
I am nit sure where to start.
volume percent is mL solute/100 mL total soln.
12.5% v/v = 12.5 mL Merlot/100 mL soln or
mL solute/mL soln = fraction.
mL solute/750 = 0.125
mL solute = 750 x 0.125 = ??
Check it to make sure it is right; i.e.,
(93.75 mL Merlot/750)*100 = 12.5%. OK.
You want the water, not the Merlot.
So if 93.75 mL = Merlot then 750-93.75 = mL H2O.
Thanks I got it and yep it is correct.
To find out how much of the liquid in the bottle is water, we need to first determine the amount of alcohol in the bottle.
We are given that the bottle contains 0.750 L of liquid and that the alcohol content is 12.5% by volume.
To find the amount of alcohol in the bottle, we can multiply the volume of the bottle by the alcohol content percentage:
Alcohol volume = 0.750 L * 0.125 = 0.09375 L
Next, we need to find the volume of water in the bottle. Since the total volume of liquid in the bottle is 0.750 L, we can calculate the volume of water by subtracting the alcohol volume from the total volume:
Water volume = 0.750 L - 0.09375 L = 0.65625 L
To convert this volume to milliliters (mL), we can multiply by 1000:
Water volume = 0.65625 L * 1000 mL/L = 656.25 mL
Therefore, there are 656.25 mL of water in the bottle.