CHEM (PLEASE HELP ASAP)

The deltaS for a reaction is 3.0 J/(mol*K) at 25 degrees C. Caluculate the deltaG for the reaction when DeltaH = -394 kL and determine whether it will occur spontaneously at this temperature

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asked by Maria
  1. delta G = delta H -T*deltaS
    You must mean -394 kJ and not kL for DH.
    What's the problem is just plugging in and getting the answer? The USUAL problem with students is they forget DH is in kJ and DS is in J.
    So you want -394 kJ -(298.15)*.003 = ?? kJ.
    If the sign is negative, the reaction is spontaneous. If +, the reaction is not spontaneous.

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    posted by DrBob222
  2. so would it be -2.0764 or do i need to move the decimal?

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    posted by Anonymous
  3. I don't know how you obtained -2.0764.
    -394-(298.15*-0.003) = -394-0.894 = ??.
    I changed 3 J/mol*K to kJ/mol*K.

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    posted by DrBob222

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