which is the equation for the axis of symmetry of y=1/2x^2 -2x -3?
a)y = -2
b)y = 2
c)x = -2
d)x = 2
Complete the square.
y = (1/2)(x^2 -4x +4) -5
= (1/2)(x-2)^2 +5
The vertex is at x=2, y = 5
There is symmetry about x = 2. The +5 constant term gives it a vertical shift but noes not affect symmetry. The 1/2 multiplier term flattens the parabola