what is the precipitate formed when benedicts solution reacts with glucose? give the net ionic equation for the reaction.
Cu(II) is reduced to Cu(I) and red Cu2O precipitates. http://en.wikipedia.org/wiki/Benedict%27s_reagent
When Benedict's solution reacts with glucose, a red precipitate of copper (I) oxide (Cu2O) is formed. The net ionic equation for this reaction is as follows:
2 Cu2+ (aq) + C6H12O6 (aq) → Cu2O (s) + 2 H+ (aq)
This equation shows the reduction of copper (II) ions to copper (I) ions, resulting in the formation of the red precipitate.
When Benedict's solution reacts with glucose, a red precipitate of copper(I) oxide (Cu2O) is formed.
To understand the net ionic equation for the reaction, let's first write the balanced equation for the reaction between Benedict's solution and glucose:
C6H12O6 + 2Cu2+ + 2OH- → Cu2O (↓) + C6H10O7 + H2O
In this equation, C6H12O6 represents glucose and Cu2O represents copper(I) oxide (the precipitate). Cu2+ and OH- ions are present in Benedict's solution.
Now, let's write the net ionic equation, which focuses on the species that participate directly in the reaction and disregards any spectator ions:
C6H12O6 + 2Cu2+ + 2OH- → Cu2O (↓) + C6H10O7 + H2O
The net ionic equation for this reaction is:
C6H12O6 + 2Cu2+ + 2OH- → Cu2O (↓) + C6H10O7 + H2O
Please note that the equation above shows the balanced net ionic equation for the reaction between Benedict's solution and glucose.