Anthroquinone (C14H8O2), an important intermediate in the dye industry, is produced from the reaction of benzene with phthalic anhydride (C8H4O3), followed by dehydration with sulfuric acid. The overall reaction is...
C8H4O3 + C6H6 --> C14H8O2 + H20
b) What mass of Anthroquinone and of H2O will be produced with a 100% yield?
[I don't want an answer, I'd just like to know how to approach this problem]
c) What percent yield is achieved if 1.96 x 10^3 g of anthro is produced? [same- how would I do this?]
For b), you know that one mole of phthalic anhydride plus one mole of benzene goes to one mole of anthroguinone plus one mole of water. I presume they tell you the mass of one of the reactants, so you can then figure out how many moles are present, then you know how many moles of anthroquinone will be produced.
Same for c): figure out how many moles that is, and go from there.
Thank you!
You're welcome!!
Somehow I think you missed an important point: what was the starting mass of phthalic anydride?
I need answer to the question
I need help on this question
I would like to see the worked steps for (b)
Apologies for missing that important point. To determine the starting mass of phthalic anhydride, you would need additional information from the problem statement. The problem should provide you with the mass of one of the reactants, which in this case could either be benzene or phthalic anhydride.
Let's assume that the problem statement provides you with the mass of benzene, which we'll call "mBenzene". To determine the starting mass of phthalic anhydride, you would need to use the molar ratio between benzene and phthalic anhydride, which is 1:1 as specified in the balanced chemical equation.
First, you need to calculate the molar mass of benzene (C6H6) and phthalic anhydride (C8H4O3). Once you have the molar mass, you can convert the given mass of benzene (mBenzene) to moles by dividing it by its molar mass.
Next, using the molar ratio between benzene and phthalic anhydride (1:1), you can determine the number of moles of phthalic anhydride that would be required for the reaction. Since the molar ratio is 1:1, the number of moles of phthalic anhydride would be the same as the number of moles of benzene.
Finally, you can convert the number of moles of phthalic anhydride to mass by multiplying it by the molar mass of phthalic anhydride. This will give you the starting mass of phthalic anhydride.
To summarize the steps:
1. Calculate the molar mass of benzene and phthalic anhydride.
2. Convert the given mass of benzene (mBenzene) to moles.
3. Use the molar ratio between benzene and phthalic anhydride to determine the number of moles of phthalic anhydride.
4. Convert the number of moles of phthalic anhydride to mass by multiplying it by the molar mass of phthalic anhydride.
I hope this helps you correctly approach the problem. If you have the mass of phthalic anhydride or any further questions, feel free to ask!