Calculate the boiling point elevation of a solution made from 15.0 g of a nonelectrolyte solute and 250.0 g of water. the molar mass of the solute is 50.0 g and Kb = 0.51 degrees C/m
Well, don't expect me to put on a lab coat and goggles! But let's dive into this question and uncover the answer, shall we?
To calculate the boiling point elevation, we'll use the formula:
ΔTb = Kb * m * i
Where:
- ΔTb is the boiling point elevation
- Kb is the molal boiling point elevation constant
- m is the molality of the solution
- i is the vant Hoff factor (which is 1 for a nonelectrolyte solute)
First, we need to find the molality of the solution. We can calculate it using the formula:
m = moles of solute / mass of solvent (in kg)
Given that we have 15.0 g of nonelectrolyte solute and 250.0 g of water, we can convert those values to kg:
mass of solute = 15.0 g = 0.015 kg
mass of solvent (water) = 250.0 g = 0.250 kg
Now, let's find the molality:
m = 0.015 kg / 0.250 kg
m = 0.06 m
Since the solute is a nonelectrolyte, the vant Hoff factor (i) is 1.
Finally, using the formula for boiling point elevation:
ΔTb = 0.51 degrees C/m * 0.06 m * 1
ΔTb = 0.03 degrees C
So, the boiling point elevation of the solution is 0.03 degrees Celsius. Just be warned, water might get a bit hotter when you add 15.0 grams of nonelectrolyte solute to it. Just keep your ice popsicles handy!
To calculate the boiling point elevation of a solution, you need to use the formula:
ΔTb = Kbm
Where:
ΔTb = boiling point elevation
Kb = boiling point elevation constant (provided as 0.51°C/m)
m = molality of the solution
To calculate the molality of the solution, first find the number of moles of the solute. You can use the formula:
moles = mass / molar mass
Given that the mass of the solute is 15.0 g and the molar mass is 50.0 g/mol:
moles = 15.0 g / 50.0 g/mol = 0.3 mol
Next, you need to calculate the molality, which is defined as the number of moles of solute per kilogram of solvent (water in this case). Since you have 250.0 g of water, which is equivalent to 0.250 kg:
molality = moles of solute / mass of solvent in kg
= 0.3 mol / 0.250 kg
= 1.2 mol/kg
Now that you have the molality (m), you can calculate the boiling point elevation:
ΔTb = Kb * m
= 0.51°C/m * 1.2 mol/kg
= 0.612°C
Therefore, the boiling point elevation of the solution is 0.612°C.
moles = grams/molar mass.
Calculate moles.
m = moles/kg solvent
Calculate m
delta T = Kb*m
calculate delta T.