in each game there are 12 red checkers and 12 black checkers.If tom put all the checkers in the bag and randomly picked 2,what is the probability that both will be black?
that would simply be
(12/24)((11/23)
= ...
In a given parking lot there is a 1/2 chance a parking space will have a white car and 1/2 chance it will have a black car. if you monitor a random parking space for three days, what is the probability it will have a black car parked in it at least 2 days
In a game of checkers or 12 reggae and pieces and 12 black game pieces Julio was sitting up the board to begin playing what is the probability of the first to Schuckers he pulls out at a random will be to re in a game of checkers or 12 reggae and pieces and 12 black game visas Julio was sitting up the board to begin playing what is the probability of the first to Schuckers he pulls out at a random will be two red
To find the probability that both checkers will be black, we first need to determine the total number of possible outcomes and the number of favorable outcomes.
The total number of possible outcomes can be found using the concept of combinations. Since Tom is picking 2 checkers from a set of 24 (12 red and 12 black), we can calculate the total number of combinations using the formula:
nCr = n! / (r!(n-r)!)
In this case, n = 24 (total number of checkers) and r = 2 (number of checkers Tom is picking).
Therefore, the total number of possible outcomes is:
24C2 = 24! / (2!(24-2)!) = 24! / (2! * 22!) = (24 * 23) / (2 * 1) = 276.
Next, we need to determine the number of favorable outcomes. Since we want both checkers to be black, there are 12 black checkers to choose from for the first pick and 11 black checkers remaining for the second pick. So the number of favorable outcomes is:
12C1 * 11C1 = 12! / (1!(12-1)!) * 11! / (1!(11-1)!) = (12 * 11) / (1 * 1) = 132.
Finally, we can calculate the probability by dividing the number of favorable outcomes by the total number of possible outcomes:
P(both black) = favorable outcomes / total outcomes = 132 / 276 = 0.478 or 47.8%.
Therefore, the probability that both checkers picked by Tom will be black is approximately 0.478 or 47.8%.