Okay I got this question on a test. I am not sure what I am supposed to do here. Can you show me how I would go about solving this.
A basketball player can jump 33in vertically. Find his hang time. Round to the nearest tenth.
Thanks
The time to drop in free-fall for 33 inches (2.75') can be calculated by solving for:
S=ut+(1/2)gt²
2.75=0*t + (1/2)(32.2)t²
t=√(2*2.75/32.2)
=0.41 sec.
Thus time he is off-ground =2*0.41 sec=0.82 sec.
What's that formula called?
where did you get that 32.2 from?
To find the hang time of a basketball player, we can use the formula:
Hang time = (2 * jump height) / acceleration due to gravity
The acceleration due to gravity is approximately 32.2 ft/s^2.
In this case, the jump height is given as 33 inches. We need to convert it to feet in order to be consistent with the unit of acceleration due to gravity.
1 foot is equal to 12 inches, so to convert inches to feet, divide the jump height by 12:
33 inches / 12 = 2.75 feet
Now we can substitute the values into the formula:
Hang time = (2 * 2.75 feet) / 32.2 ft/s^2
Calculating this equation will give us the hang time in seconds. Round the answer to the nearest tenth as requested.