what is the theoretical value for the M of acetic acid in vinegar if the vinegar is 5% acetic acid by a % mass value.
Additional info: the experimental M of the acetic acid in vinegar is 0.80M
Thank you!!
It isn't possible to calculate the theoretical molarity of vinegar without know the density. I tried looking up the density of vinegar on the net and found values all the way from 0.96 g/mL to 1.08 g/mL (and some said 5% by mass and other 5% by volume).
5% by mass vinegar means 5 g CH3COOH/100 g solution. 5 g is 5/60.05 = 0.083 moles/100 g soln. If the density of the vinegar is 1.00 g/mL then the M = 0.083/0.1 = 0.83 M.
If you know the density, then volume = mass/density = 100/density and moles/L = M.
To find the theoretical value for the molarity (M) of acetic acid in vinegar, we need to use the information provided:
1. The vinegar is 5% acetic acid by mass.
2. The experimental Molarity (M) of acetic acid in vinegar is 0.80M.
To start, we'll convert the percentage mass of acetic acid to grams:
1. Assume you have 100 grams of vinegar since percentage mass is given.
2. Since the vinegar is 5% acetic acid, 5 grams of the 100 grams is acetic acid.
Next, we'll calculate the number of moles of acetic acid:
1. Acetic acid has a molar mass of approximately 60.05 g/mol.
2. Divide the grams of acetic acid (5 g) by the molar mass to get the number of moles: 5 g / 60.05 g/mol ≈ 0.083 moles.
Now we can calculate the theoretical Molarity (M) of acetic acid in vinegar:
1. Molarity (M) is defined as moles of solute per liter of solution.
2. Since we have determined 0.083 moles of acetic acid, we need to find the volume of the solution in liters to calculate the Molarity.
3. Assume you have 1 liter of vinegar (1000 mL) since the volume is not given.
Using the volume and moles of solute, we can calculate the Molarity:
Molarity (M) = Moles of solute / Volume of solution in liters
Molarity (M) = 0.083 moles / 1 liter = 0.083 M
Therefore, the theoretical Molarity (M) of acetic acid in vinegar, based on the given information, is 0.083 M.
To calculate the theoretical value for the molarity (M) of acetic acid in vinegar, we need to use the relationship between mass, molar mass, and molarity.
First, we need to find the mass of acetic acid in vinegar. If the vinegar is 5% acetic acid by mass, that means that for every 100g of vinegar, 5g is acetic acid.
Next, we need to determine the molar mass of acetic acid, which is C2H4O2. To calculate the molar mass, we add up the atomic masses of carbon (C), hydrogen (H), and oxygen (O):
C: 12.01 g/mol
H: 1.01 g/mol
O: 16.00 g/mol
Molar mass of acetic acid (C2H4O2):
(2 * 12.01 g/mol) + (4 * 1.01 g/mol) + (2 * 16.00 g/mol) = 60.05 g/mol
Now, using this information, we can calculate the molarity of acetic acid in vinegar using the formula:
Molarity (M) = moles of solute / volume of solution (in liters)
Since we know the mass of acetic acid and the molar mass, we can calculate the moles of acetic acid:
moles = mass / molar mass
moles of acetic acid = 5g / 60.05 g/mol = 0.0833 mol
The experimental Molarity (M) of the acetic acid in vinegar is given as 0.80M.
Therefore, the theoretical value for the Molarity (M) of acetic acid in vinegar, assuming the percentage by mass is accurate, would be 0.0833 M.