The flower peddler has red flowers with five petals each and white flowers with eight petals each. He has a total of 11 flowers with a total of 76 petals. How many red flowers are there and how many white flowers?
Well, it seems like the flower peddler has a bit of a mixed bouquet going on. Let's do some petal calculations, shall we?
Let's say there are x red flowers and y white flowers. We know that each red flower has 5 petals and each white flower has 8 petals. So, the total number of petals can be expressed as 5x + 8y.
We also know that the total number of flowers is 11, so we can put that into an equation as well: x + y = 11.
Now, since we're all about finding humor in numbers, let's solve this riddle.
Combining the equations, we have:
5x + 8y = 76 (Equation 1)
x + y = 11 (Equation 2)
Now, it's time to put on our mathematician clown nose and solve this puzzle.
Multiplying Equation 2 by 5, we get:
5x + 5y = 55 (Equation 3)
Subtracting Equation 3 from Equation 1, we have:
(5x + 8y) - (5x + 5y) = 76 - 55
3y = 21
Dividing both sides by 3, we find:
y = 7
Now, let's substitute the value we found for y back into Equation 2:
x + 7 = 11
Subtracting 7 from both sides, we find:
x = 4
So, the flower peddler has 4 red flowers and 7 white flowers. Keep spreading those petals and laughter!
Let's represent the number of red flowers as "R" and the number of white flowers as "W".
We know that each red flower has 5 petals, so the total number of red flower petals would be 5R.
Similarly, each white flower has 8 petals, so the total number of white flower petals would be 8W.
According to the problem, the total number of petals is 76. So, we can write the equation:
5R + 8W = 76 (Equation 1)
We also know that the total number of flowers is 11. So, we can write another equation:
R + W = 11 (Equation 2)
Now, let's solve this system of equations to find the values of R and W.
We can start by multiplying Equation 2 by 5 to make the coefficients of R the same in both equations:
5R + 5W = 55 (Equation 3)
Next, we can subtract Equation 3 from Equation 1 to eliminate R:
5R + 8W - (5R + 5W) = 76 - 55
8W - 5W = 21
3W = 21
W = 21 / 3
W = 7
Now that we know W = 7, we can substitute this value into Equation 2 to find R:
R + 7 = 11
R = 11 - 7
R = 4
Therefore, there are 4 red flowers and 7 white flowers.
To solve this problem, we can use a system of equations. Let's represent the number of red flowers as "x" and the number of white flowers as "y."
According to the problem, the red flowers have five petals each, so the total number of red flower petals would be 5x.
Similarly, the white flowers have eight petals each, so the total number of white flower petals would be 8y.
We are given that the total number of flowers is 11. Therefore, the equation for the total number of flowers can be written as:
x + y = 11 --------(Equation 1)
We are also given that the total number of petals is 76. Thus, the equation for the total number of petals can be written as:
5x + 8y = 76 --------(Equation 2)
Now, we have a system of equations consisting of Equation 1 and Equation 2. We can solve this system to find the values of x and y.
One way to solve this system is by using the substitution method. We can solve Equation 1 for x, which gives:
x = 11 - y
Substituting this value of x into Equation 2, we get:
5(11 - y) + 8y = 76
Expanding and simplifying the equation:
55 - 5y + 8y = 76
3y = 21
y = 7
Plugging the value of y back into Equation 1:
x + 7 = 11
x = 4
Therefore, there are 4 red flowers and 7 white flowers.
Let r = # red flowers and w = # of white flowers.
5r + 8w = 76
r + w = 11
r = 11 - w
Substitute 11-w for r in the first equation to find w. Put that value in the second equation to find r. Check by putting both values in the first equation.