If the percent hydration of CuCl2 x XH2O is 13% what is the coefficient of water?
Take a 100 g sample.
grams water = 13 g
grams CuCl2 = 87.
mols CuCl2 = 87 g/molar mass CuCl2.
mols H2O = 13 g/molar mass H2O.
Now find the ratio of number of mols H2O per ONE mol CuCl2. That number will be the X in the formula. Post you work if you get stuck.
To find the coefficient of water (X) in CuCl2 x XH2O, we need to determine the percent hydration of the compound and then solve for X.
The percent hydration is given as 13%. This means that for every 100 grams of the compound, 13 grams are water.
We can set up an equation to solve for X:
(13 grams of water) / (100 grams of CuCl2 x XH2O) = (13 / 100)
To simplify the equation, we can assume that the total mass of the compound is 100 grams:
(13 grams of water) / (100 grams of CuCl2 + 100 grams of XH2O) = (13 / 100)
Since the mass of water is equal to the mass of XH2O, we can modify the equation to:
(13 grams of water) / (100 grams of CuCl2 + X grams of water) = (13 / 100)
Now, we know that CuCl2 has a molar mass of about 134.45 g/mol, and H2O has a molar mass of about 18.015 g/mol. Using these values and the molar mass relation between CuCl2 and H2O (1: X), we can rewrite the equation in moles:
(13 grams of water) / (134.45 grams of CuCl2 + X * 18.015 grams of water) = (13 / 100)
To solve for X, we can cross multiply:
13 * (134.45 + X * 18.015) = 100 * (13)
Simplifying the equation:
1748.85 + 13X * 18.015 = 1300
13X * 18.015 = 1300 - 1748.85
13X * 18.015 = -448.85
X = -448.85 / (13 * 18.015)
After performing the calculation, we find that X ≈ -1.091.
However, this value is not physically meaningful since it is negative. Therefore, it is not possible to have a negative coefficient of water in a compound. It is likely that there was an error or incorrect assumption made in the problem.