college physics

A small mass M and a small mass 3M are 1.00 m apart. Where should you put a third small mass so that the net gravitational force on it due to the other two masses is zero?

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  1. do it this way
    or 0.75m

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    posted by Aanu
  2. Gravitational force

    So for the mass m between masses M and 3M, one metre apart, equate the gravitational forces:
    GMm/x² = G(3M)m/(1-x)²
    Solve for x.

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    posted by MathMate

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