How would I go about answer this question?
If 72.26 g of hot water at 83.6 degrees C is mixed with 43.86 g of cooler wayer at 38.4 degrees C what will be the final temp of the mixture? The Cp of liquid water is 4.184 J/ g degrees C
heat lost + heat gained = 0
[mass hot water x specific heat x (Tf - Ti) + [mass cooler water x specific heat x (Tf - Ti)] = 0
Solve for Tf, the final T. Ti is initial T of each of the water samples. Post your work if you get stuck.