The reaction of aqueous iron(III) bromide and aqueous lithium phosphate is represented by the balanced ionic equation.

Fe3+(aq) + 3Br-(aq) + 3Li+(aq) + PO43-(aq) → FePO4(s) + 3Li+(aq) + 3Br-(aq)

Give the balanced formula equation for the reaction. Include the states.

I got..
FeBr3(aq)+ Li3(PO4(aq)
→FePO4(s)+3LiBr(aq)

is this right?

nvm I got the answer

No, your balanced formula equation is not correct. The correct balanced formula equation for the reaction is:

FeBr3(aq) + 3Li3PO4(aq) → FePO4(s) + 3LiBr(aq)

This equation shows that aqueous iron(III) bromide (FeBr3) reacts with aqueous lithium phosphate (Li3PO4) to form solid iron(III) phosphate (FePO4) and aqueous lithium bromide (LiBr).

Remember to balance the equation by ensuring that the number of atoms on both the left and right sides are equal.

Your balanced formula equation is almost correct, but there is a small mistake in the state of the species involved. Here is the correct balanced formula equation for the reaction with included states:

2FeBr3(aq) + 3Li3PO4(aq) → Fe2(PO4)3(s) + 6LiBr(aq)

Explanation on how to get the answer:

To balance the equation, you must ensure that the number of atoms of each element is the same on both sides of the equation.

Given the balanced ionic equation:
Fe3+(aq) + 3Br-(aq) + 3Li+(aq) + PO43-(aq) → FePO4(s) + 3Li+(aq) + 3Br-(aq)

First, identify the cations and anions that are present in both sides of the equation:
Cations: Fe3+, Li+
Anions: Br-, PO43-

Next, balance the cations and anions separately. In this reaction, we can see that there are already three Li+ cations on both sides of the equation, so they are already balanced.

Now, focus on balancing the Fe3+ ion. Since there is only one FePO4 formed on the right side, you need to have two Fe3+ ions on the left side to balance it.

To balance the Br- ions, since there are three Br- ions on both sides of the equation, they are already balanced.

Finally, to balance the PO43- ions, you need six Li3PO4 on the left side of the equation to match the three Fe2(PO4)3 formed on the right side of the equation.

The final balanced formula equation with states is:
2FeBr3(aq) + 3Li3PO4(aq) → Fe2(PO4)3(s) + 6LiBr(aq)

I hope this helps clarify the balanced formula equation for the reaction!