Calculate the volume ( mL ) of the solute C2H5OH and the mass ( g ) of the solvent diethyl ether that should be mixed to produce 3.46 kg of a solution that is 1.31 m C2H5OH.
volume ( mL ) of the C2H5OH
mass ( g ) of the (C2H5)2O
Molar Mass (g/mol)
C2H5OH 46.07
(C2H5)2O 74.12
Density ( g/mL )
C2H5OH 0.7893
(C2H5)2O 0.7138
Name/Formula
ethanol
C2H5OH
diethyl ether
(C2H5)2O
I got 249.5ml
and 3263g
is that right?
To calculate the volume of the solute C2H5OH and the mass of the solvent diethyl ether, we need to use the formula:
Mass = Volume × Density
First, let's calculate the volume of C2H5OH:
Given:
Molar Mass of C2H5OH = 46.07 g/mol
Molarity of the solution = 1.31 mol/L
To find the volume of the solute C2H5OH, we can use the formula:
Volume of solute = Mass of solute / Molar Mass
Mass of solute = Molarity × Molar Mass × Volume of solution
Mass of solute = 1.31 mol/L × 46.07 g/mol × 3.46 kg = 204.99 g
Now, let's calculate the volume of C2H5OH using the density of C2H5OH:
Volume of C2H5OH = Mass of C2H5OH / Density of C2H5OH
Volume of C2H5OH = 204.99 g / 0.7893 g/mL = 259.97 mL
So, the volume of solute C2H5OH is approximately 259.97 mL.
Now, let's calculate the mass of the solvent diethyl ether:
Given:
Density of diethyl ether (C2H5)2O = 0.7138 g/mL
Total mass of the solution = 3.46 kg = 3460 g
Mass of solvent = Total mass of solution - Mass of solute
Mass of solvent = 3460 g - 204.99 g = 3255.01 g
So, the mass of the solvent diethyl ether is approximately 3255.01 g.
Therefore, your calculation is incorrect:
Volume (mL) of C2H5OH should be approximately 260 mL.
Mass (g) of (C2H5)2O should be approximately 3255 g.