algebra

What is the approximate value of sqrt()7?

a) 1.9
b) 2.2
c) 1.5
d) 2.6

  1. 👍 0
  2. 👎 0
  3. 👁 48
asked by kim
  1. √9 = 3 and √4 = 2. Is 7 closer to 4 or 9?

    1. 👍 0
    2. 👎 0
    posted by PsyDAG

Respond to this Question

First Name

Your Response

Similar Questions

  1. Math

    How do you find a square root of a number that's not a perfect square? I'm very confused. The book doesn't explain it too well. You can approximate it or simplify it in terms of (products of) square roots of smaller numbers. E.g.

    asked by Emily on February 12, 2007
  2. Math:)

    A person is on the outer edge of a carousel with a radius of 20 feet that is rotating counterclockwise around a point that is centered at the origin. What is the exact value of the position of the rider after the carousel rotates

    asked by girly girl on March 22, 2018
  3. Math Help please!!

    Could someone show me how to solve these problems step by step.... I am confused on how to fully break this down to simpliest terms sqrt 3 * sqrt 15= sqrt 6 * sqrt 8 = sqrt 20 * sqrt 5 = since both terms are sqrt , you can combine

    asked by Reggie on May 20, 2007
  4. math,algebra,help

    Directions are simplify by combining like terms. x radiacal 18 -3 radical 8x^2 can someone show me how to do these types of problems. thanks I cant determine the second term. For the first, I think you meant x sqrt(18) which

    asked by Jasmine20 on January 26, 2007
  5. Calculus

    Please look at my work below: Solve the initial-value problem. y'' + 4y' + 6y = 0 , y(0) = 2 , y'(0) = 4 r^2+4r+6=0, r=(16 +/- Sqrt(4^2-4(1)(6)))/2(1) r=(16 +/- Sqrt(-8)) r=8 +/- Sqrt(2)*i, alpha=8, Beta=Sqrt(2) y(0)=2,

    asked by COFFEE on July 10, 2007
  6. Math(Roots)

    sqrt(24) *I don't really get this stuff.Can somebody please help me? The square root of 24 is 4.898979485566356 I know that..lol,but it says not to use decimals.Here is an example they gave me. Ex.sqrt(18)=sqrt(2*3*3)=3sqrt(2)

    asked by Margie... on December 18, 2006
  7. Inequality

    When I solve the inquality 2x^2 - 6 < 0, I get x < + or - sqrt(3) So how do I write the solution? Is it (+sqrt(3),-sqrt(3)) or (-infinity, sqrt(3))? Why? Thanks. So would this work? abs x < ( sqrt 3 ) or - sqrt 3

    asked by Jen on November 5, 2006
  8. Algebra

    Evaluate sqrt7x (sqrt x-7 sqrt7) Show your work. sqrt(7)*sqrt(x)-sqrt(7)*7*sqrt(7) sqrt(7*x)-7*sqrt(7*7) sqrt(7x)-7*sqrt(7^2) x*sqrt 7x-49*x ^^^ would this be my final answer?

    asked by Alexa on February 17, 2016
  9. Algebra

    Please help me to solve this Radical Expressions and equations word problem. Here is the question: Surveying. The length of each lot line of a swimming pool complex is shown. Find the exact perimeter of the irregular shaped lot.

    asked by Jay on November 22, 2014
  10. Math/Calculus

    Solve the initial-value problem. Am I using the wrong value for beta here, 2sqrt(2) or am I making a mistake somewhere else? Thanks. y''+4y'+6y=0, y(0)=2, y'(0)=4 r^2+4r+6=0, r=(-4 +/- sqrt(16-4(1)(6))/2 r=-2 +/- sqrt(2)*i , alpha

    asked by COFFEE on July 12, 2007
  11. calculus

    Use x=-1/2 in the MacLaurin series for e^x to approximate 1/sqrt (e) to four decimal places. So far I have |f^n(0)/n! (1/sqrt(e)-1/2)^n)|

    asked by Camryn on August 2, 2017

More Similar Questions