a basetball team has won 50 games of 75 played.the team still have 45 games to play.how many of the remaining games must the team win in order to win 60% of all the games during the season?

a)20
b)22

"All the games" played would be 75 + 45. Caculate 60% (.6) of that total and subtract 50 from that product to get your answer.

I hope this helps you to understand the process in reaching the answer. Thanks for asking.

20

Your high school softball team won 80% of the games it played this year.If your team won 20 games, how many games did it play?

To determine the number of remaining games the team needs to win in order to achieve 60% of all the games during the season, follow these steps:

Step 1: Calculate the total number of games in the season.
The team has already played 75 games and still has 45 games left to play. So the total number of games in the season is 75 + 45 = 120.

Step 2: Calculate 60% of the total number of games.
To find 60% of 120 games, multiply 120 by 0.60: 120 x 0.60 = 72.

Step 3: Determine the number of games the team has already won.
The team has won 50 games.

Step 4: Calculate the number of games the team needs to win in order to achieve 60%.
Subtract the number of games already won from the target number of games to win: 72 - 50 = 22.

Therefore, the team needs to win 22 of the remaining 45 games in order to win 60% of all the games during the season. Hence, the answer is option b) 22.