algebra

if (2 -q) is one factor of 4 - 2q - 6p + 3pq, what is the other factor?

a) 2 + 3p
b) 2 - 3p
c)3p - 2
d) 2 - 3q

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1. You can use long division

(4 - 2q - 6p + 3pq)/(2-q)

2
2*(2-q) = 4-2q
subtract result is
-6 p + 3 q
divide by (2-q)
-3p
-3p(2-q) = -6p +3pq
subtract, result is zero (remainder is 0
so
2-3p is the other factor

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posted by Damon

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