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math 012
will someone please double check my answer to this problem. the answer i get is a fraction, but not sure how to type it on here. 4(4y+2)=2(1+6y)+8 16y+8=2+12y+8 16y+8=10+12y 16 16 8=6+12y +6 +6 14=12y divide both by 12 and that
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If 5x +4y and 4x +3y =5 15x +12y =18 16x +12y = 20 31x/31= 38/31 x= 1 7/31 20x +16y =24 20x +15y = 5 31/y/31 = 29/31 y=29/31 x +y = 1 7/31 + 29/31 2 5/31
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If 5x +4y and 4x +3y =5 15x +12y =18 16x +12y = 20 31x/31= 38/31 x= 1 7/31 20x +16y =24 20x +15y = 5 31/y/31 = 29/31 y=29/31 x +y = 1 7/31 + 29/31 2 5/31
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