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algebra
24x^412x^3+48x^2/4x 24x^412x^3+12(1) 24x^412x^3+(12x) 2x^412x^312x check this problem for me please
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Rewrite the polynomial in descending order in its simplest form. here is #1 12x^2 y^2 z^3+2+24x^2 I think it should be writen 12x^2y^2Z^3+24x^2+2 then there is also question #6 I need help with is it x+y+xy+3x+4x^2 I think it
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Can someone help me with this please. Andrew factored the expression 20x^312x^2+8x as 4x(5x^212x^2+8x) but when melissa applied the distributive law and multiplied out 4x(5x^212x^2+8x)she got 20x^348x^3+32x thus Andrews
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1/3  5/6 = 1/X SOLVE 1/3  5/6 = 1/X Let's remove the denominators by multiplying by 12X 12X*(1/3)  12X*(5/6) = 12X*(1/X) Clear the fractions. 4X  10X = 12 6X=12 multipy by 1 6X=12 Divide both sides by 6 6X/6 = 12/6 X = 2
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Andrew factored the expression 20x^312x^2+8x as 4x (5x^212x^2+8x). But when Melissa applied the distributive law and multiplied out 4x (5x^212x^2+8x), she got 20x^348x^3+32x^2; thus, Andrewâ€™s solution does not appear to
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