4. 8 bolts and 6 nuts weigh 138 grams. 3 bolts and 5 nuts weigh 71 grams. Work out the weight of the following:-

(a) 4 bolts and 3 nuts
(b) 11 bolts and 11 nuts
(c) 3 bolts and 3 nuts
(d) 1 bolt

follow this method:

Ingredients

For the marinade

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600ml/1 pint buttermilk
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6 tbsp coriander, chopped
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6 garlic cloves, finely chopped
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2 shallots, finely chopped
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½ tsp dried chilli flakes
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1 tbsp salt
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4 x 175g chicken breasts, skinless

For the coating

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6 tbsp plain flour
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½ tsp celery salt
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½ tsp cayenne pepper
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½ tsp ground black pepper
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½ tsp paprika

To cook the chicken

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200ml vegetable oil

For the coleslaw

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¼ red cabbage, finely shredded
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¼ white cabbage, finely shredded
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3 carrots, shredded
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4 spring onions, chopped
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1 tbsp caraway seeds
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1 tbsp chilli sauce
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100g/4oz mayonnaise
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salt and freshly ground black pepper

Preparation method

1.

For the marinade, combine all the ingredients for the marinade and coat the chicken in a shallow dish. Cover and leave to marinate overnight in the fridge.
2.

Combine all the ingredients for the coating. Remove the chicken from the marinade and dip into the spiced flour. Coat thoroughly and return to the fridge for a further 45 minutes.
3.

Preheat the oven to 200C/400F/Gas 6.
4.

Heat the vegetable oil to in a deep heavy-bottomed saucepan, until a breadcrumb sizzles and browns when dropped in it. (CAUTION: hot oil can be dangerous - do not leave unattended!). Add the chicken and fry until golden all over. Remove and place on a baking sheet.
5.

Transfer to the oven and cook for 15-20 minutes until cooked through.
6.

For the coleslaw, mix all of the ingredients together and season to taste.

To solve this problem, we can set up a system of equations to represent the given information. Let's use variables to denote the weight of one bolt and one nut.

Let's say the weight of one bolt is "x" grams and the weight of one nut is "y" grams.

Using this information, we can form two equations:

Equation 1: 8x + 6y = 138 (from the first statement)
Equation 2: 3x + 5y = 71 (from the second statement)

Now, let's solve these equations to find the values of x and y.

To solve this system of equations, we can use a method called substitution or elimination. Let's use substitution method here.

First, solve equation 2 for x in terms of y:
3x = 71 - 5y
x = (71 - 5y) / 3

Now substitute this value of x in equation 1:
8((71 - 5y) / 3) + 6y = 138

Simplify this equation to solve for y:
568 - 40y + 18y = 414
-22y = -154
y = 7

Now substitute the value of y back into equation 2 to solve for x:
3x + 5(7) = 71
3x = 71 - 35
3x = 36
x = 12

So, we have found that the weight of one bolt (x) is 12 grams and the weight of one nut (y) is 7 grams.

Now, let's answer the given questions:

(a) 4 bolts and 3 nuts:
The weight of 4 bolts = 4 * 12 = 48 grams
The weight of 3 nuts = 3 * 7 = 21 grams
Total weight = 48 + 21 = 69 grams

(b) 11 bolts and 11 nuts:
The weight of 11 bolts = 11 * 12 = 132 grams
The weight of 11 nuts = 11 * 7 = 77 grams
Total weight = 132 + 77 = 209 grams

(c) 3 bolts and 3 nuts:
The weight of 3 bolts = 3 * 12 = 36 grams
The weight of 3 nuts = 3 * 7 = 21 grams
Total weight = 36 + 21 = 57 grams

(d) 1 bolt:
The weight of 1 bolt = 12 grams