Algebrq

How do i solve

sqr4z+3=4sqr3. thé 4z+3 is under thé radical

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1. √(4z+3)=4√3
Square both sides to remove the radical,
4z+3 = 16*3 = 48
4z = 48-3 = 45
z = 45/4=11.25

Note: you can type the √ symbol with
& r a d i c ;
but without the spaces.

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