math

how do i solve the sum of the first n even positive integers is h. the of the first n odd positive integers is k. determine the value of h-k, in terms of n

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  1. for n = 3
    h = 2+4+6 = 12
    k = 1+3+5 = 9
    -------------- subtract
    h-k 1+1+1 = 3

    h - k = 3 for n = 3
    In fact you get one more for every increase of n by 1
    so
    ah ha
    h-k = n

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