I need help solving this quadratic equation.
4x^2=13x+12
Remember to add or subtract terms to get all terms on one side of the equals and zero in the other side. Then, plug the coeffecients into the quadratic equation.
Just do what Quidditch says and remember the quadratic formula is x= -b plus or minus square root of (b^2-4ac) all over 2a.
Sorry I'm on a laptop and can't do the plus or minus symbol.
Sure! To solve the quadratic equation 4x^2 = 13x + 12, we need to set it equal to zero and then use either factoring, completing the square, or the quadratic formula.
First, let's rearrange the equation to bring all terms to one side:
4x^2 - 13x - 12 = 0
Now, we can try factoring the equation. We need to find two numbers that multiply to give -48 (product of the coefficient of x^2 and the constant term) and add up to -13 (coefficient of x):
The factors of -48 that add up to -13 are -16 and 3.
So, we can rewrite the quadratic equation as:
(4x + 3)(x - 4) = 0
Now, we can set each factor equal to zero and solve for x:
4x + 3 = 0 or x - 4 = 0
Solving for x in the first equation:
4x = -3
x = -3/4
Solving for x in the second equation:
x = 4
Therefore, the solutions to the quadratic equation 4x^2 = 13x + 12 are x = -3/4 and x = 4.