You dip your finger into a pan of water twice each second, producing waves with crests that are separated by 0.15 m. Determine the frequency, period, and speed of these water waves.
Twice a second is frequency = 2 Hz
The period is therefore 1/2 = 0.5 seconds
In .5 seconds the wave goes .15 meters so its speed is
.15/.5 = .30 m/s
Well, that finger sure is quite the wave-maker! Let's dive into the calculations:
Frequency is defined as the number of waves produced per second. Since you're dipping your finger twice each second, the frequency would be 2 waves.
The period is the time it takes for one complete wave to pass a fixed point. In this case, it would be 1/2 seconds per wave, since you're dipping your finger twice each second (2 waves per second).
Now, let's calculate the speed of these water waves. The speed (v) of a wave is given by the formula v = λ × f, where λ is the wavelength and f is the frequency.
We can find the wavelength (λ) by dividing the distance between crests (0.15 m) by the number of crests (waves) produced per second (2). So, λ = 0.15 m / 2 = 0.075 m.
Now, we can calculate the speed (v) using v = λ × f = 0.075 m × 2 = 0.15 m/s.
So, the frequency of the water waves is 2 waves/second, the period is 1/2 seconds/wave, and the speed is 0.15 m/s.
Hats off (or should I say, waves off?) to your finger for making such a splash!
To determine the frequency, period, and speed of the water waves, we can make the following calculations:
1. Frequency (f): The frequency is the number of waves produced per second. In this case, you dip your finger into the pan twice each second. Therefore, the frequency is 2 waves/second.
2. Period (T): The period is the time taken to produce one wave. It is the inverse of the frequency. So, T = 1/f. In this case, T = 1/2 = 0.5 seconds.
3. Speed (v): The speed of a wave can be calculated by multiplying its frequency (f) by its wavelength (λ), where the wavelength is the distance between two consecutive crests. In this case, the distance between crests is given as 0.15 m.
v = f * λ
v = 2 waves/second * 0.15 m/wave
v = 0.3 m/second
Therefore, the frequency is 2 waves/second, the period is 0.5 seconds, and the speed of these water waves is 0.3 m/second.
To determine the frequency, period, and speed of the water waves, we can use the following formulas:
Frequency (f) = 1 / Period (T)
Speed (v) = wavelength (λ) * Frequency (f)
First, let's determine the period (T):
The given information states that you dip your finger into the water pan twice each second, so the period is the inverse of this frequency. Therefore, T = 1 / 2 = 0.5 seconds.
Next, let's determine the wavelength (λ):
The problem states that the crests of the waves are separated by 0.15 m. Since the wavelength is the distance between successive crests, λ = 0.15 m.
Now, we can calculate the frequency (f) using the formula:
Frequency (f) = 1 / Period (T)
Substituting the given period, we have f = 1 / 0.5 = 2 Hz (cycles/second).
Lastly, we can determine the speed (v) of the water waves using the formula:
Speed (v) = Wavelength (λ) * Frequency (f)
Substituting the given wavelength and frequency, we get v = 0.15 m * 2 Hz = 0.3 m/s.
Therefore, the frequency of the water waves is 2 Hz, the period is 0.5 seconds, and the speed is 0.3 m/s.
frequency= 2waves/sec
wavelength= .15m
speed= 2hz*.15m= .30m/sec