algebra

what are the factor of the following trinomial?

3t^2 + 19t + 6

a) (t + 1)(3t + 6)
b) (3t + 1)(t + 6)
c) (t - 1) (3t + 6)
d) (3t - 1) (t + 6)

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  1. If we note that 19=3*6+1*1, we would choose the answer where all signs are positive, and which gives the term 18t².

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  2. Look at answer (b).

    Step 1.

    Multiply 3t by t

    Step 2.

    Multiply 3t by 6

    Step 3.

    Multiply 1 by t

    Step 4.

    Multiply 1 by 6

    That gives you

    3t^2+18t+t+6

    Step 5.

    End Result

    3t^2 + 19t + 6

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