Vector

Determine the perimeter and area of the tirangle whose vertices are the origin and the x and y intercepts of the line (x-6)/3 = (y+8)/-2

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  1. when x = 0
    -3=(y+8)/-2
    6 = y + 8
    y = -2
    so (0,-2) vertex
    when y = 0
    (x-6)= 3 (8/-2)
    x-6 = -12
    x = -6
    so (-6,0) vertex
    base = 6
    height = 2
    area = (1/2)(6)(2) = 6
    You do the hypotenuse and add it to the legs.

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