# Vector

Determine the perimeter and area of the tirangle whose vertices are the origin and the x and y intercepts of the line (x-6)/3 = (y+8)/-2

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1. when x = 0
-3=(y+8)/-2
6 = y + 8
y = -2
so (0,-2) vertex
when y = 0
(x-6)= 3 (8/-2)
x-6 = -12
x = -6
so (-6,0) vertex
base = 6
height = 2
area = (1/2)(6)(2) = 6
You do the hypotenuse and add it to the legs.

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