determine the volume of stock acid required to prepare 500mL of 0.5mol/L hydrochloric acid. Assume the stock acid is 38% by mass hydrogen chloride and has a density of 1190kg/m3 (1.190g/mL)

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  1. assume one liter of stock.

    mass stock= 1190g
    mass HCL= 1138*.38=432g
    moles HCL= 432/37=11.7

    so you want to dilute it 11.7/.5=23.4times
    so you need one part stock, 22.4 parts water.

    each part= 500ml/23.4=21.4ml

    21.4ml stock
    479 ml H2O

    check me.

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