Assuming that a typical popular music CD comprises 12 songs each of 8500 KB, what would the effective transmission speed need to be capped at in order to extend the download time to 2 hours? Express your final answer in bits per second, using scientific notation correct to two decimal places.

duplicate post; answered elsewhere

Cue dodnevd

To find the effective transmission speed in bits per second, we'll need to calculate the total data that needs to be downloaded and divide it by the download time.

First, let's calculate the total data size of the CD:
12 songs * 8500 KB/song = 102000 KB

Next, convert the data size into bits:
102000 KB * 8 bits/KB = 816000 bits

Now, we need to find the download speed required to download this data within 2 hours. We'll convert 2 hours into seconds:
2 hours * 60 minutes/hour * 60 seconds/minute = 7200 seconds

Finally, divide the total data size by the download time to find the effective transmission speed:
816000 bits / 7200 seconds = 113.33 bits/second

Expressing this in scientific notation correct to two decimal places:
1.13 x 10^2 bits/second

Therefore, in order to extend the download time to 2 hours, the effective transmission speed needs to be capped at 1.13 x 10^2 bits/second.