If 36 g of potassium chloride are dissolved in 100mL of water at 40 C to form a saturated solution, how many grams of potassium chloride would be required to form a saturated solution in 250 mL of water at the same temperature?

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  1. 250mL/100mL=1.5
    36g * 2.5=90g

    90 grams KCl (potassium chloride) will be needed to make a saturated solution in 250 mL of water at 40 degrees C.

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  2. That's really easy.
    you do 250/100 which is 2.5
    then, you multiply that to the mass of KCl and get 90g like what the other person said.

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