calculus

p(x)=5x^3-4x^2+20-16

use synthetic division to show that x=2i is a zero of p(x)

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  1. Your function, which I will assume was to be
    p(x) = 5x^3 - 4x^2 + 20x - 16 , factors very nicely by grouping

    p(x) = 5x^3 - 4x^2 + 20x - 16
    = x^2(5x-4) + 4(5x-4)
    = (5x-4)(x^2 + 4)

    so the zeros are
    x = 4/5 and x = ± 2i

    Using synthetic division for this expression is totally out of place.

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  2. lim x�¨�‡ 2x 3 +5x 2 −x 3 =

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