Calculate the boiling point elevation of a solution containing 50.0 g of glucose dissolved in 500.0 g of water?
We just started learning about this and i don't get it!
To calculate the boiling point elevation of a solution, you need to use the equation:
ΔTb = Kb * m * i
Where:
- ΔTb is the boiling point elevation
- Kb is the molal boiling point elevation constant (specific to the solvent, in this case, water)
- m is the molality of the solute (glucose)
- i is the van't Hoff factor, which represents the number of particles formed in the solution when the solute dissolves (1 for glucose)
1. First, calculate the molality (m) of the solute (glucose) using the formula:
m = moles of solute / mass of solvent (in kg)
To do this, you'll need to convert the mass of glucose and water to moles.
The molar mass of glucose (C6H12O6) is approximately 180 g/mol. Therefore, the number of moles of glucose can be calculated as follows:
moles of solute = mass of glucose / molar mass of glucose
2. Calculate the mass of the solvent (water) in kg:
mass of solvent (in kg) = mass of water / 1000
3. Now, you can calculate the molality (m) by substituting the values into the equation from Step 1.
4. Look up the molal boiling point elevation constant (Kb) for water. Its value is approximately 0.512 °C/m.
5. Calculate the boiling point elevation (ΔTb) using the equation:
ΔTb = Kb * m * i
Substitute the values of Kb, m, and i into the equation.
Remember to keep track of units and conversions to ensure consistent results.
So, following these steps, you can calculate the boiling point elevation of the given solution containing 50.0 g of glucose dissolved in 500.0 g of water.