SQUARE ROOT of 8/3 + SQUARE ROOT of 2/3
Please see the information that Writeacher posted for you.
http://www.jiskha.com/display.cgi?id=1191442163
Is there something about her answer that you don't understand?
I would check to see if the problem is maybe the square root of 8/3 * the square root of 2/3. Maybe I am wrong, but I would look at the problem again to be sure it is definitely a sum and not a product. There is a benefit to it being a product.
To calculate the square root of a fraction, you need to find the square root of both the numerator and the denominator separately. Let's break down the calculation:
1. Square root of 8/3:
- Calculate the square root of the numerator: √8 = 2√2
- Calculate the square root of the denominator: √3
- So, the square root of 8/3 = 2√2/√3
2. Square root of 2/3:
- Calculate the square root of the numerator: √2
- Calculate the square root of the denominator: √3
- So, the square root of 2/3 = √2/√3
Now, adding both results together:
2√2/√3 + √2/√3
To add these two fractions, the denominators must be the same. Since they have a common denominator (√3), we can combine them:
(2√2 + √2)/√3
Now, simplify by combining like terms in the numerator:
3√2/√3
To rationalize the denominator (removing the square root from the denominator), multiply the numerator and denominator by √3:
(3√2)(√3)/(√3)(√3)
Simplify:
(3√6)/3
Now, cancel out the common factor of 3:
√6
Thus, the square root of 8/3 + the square root of 2/3 is √6.