ok so here's the question- For the compound Ge[S(CH2)4 CH3]4, determine:
a) the ratio, by number, of C atoms to H atoms
b) the ratio, by mass, of Ge to S
I know this can't be THAT hard...but I'm really not sure on how to get the ratio. for a would I just add up the atoms for C and H and that would be the ratio? Like 8:20 and then do the same thing for mass?? Im lost!
Thanks for the help!
yes to both but reduce to smallest fraction if the ratio is reducible.
so like if the ratio was 2:4 it would become 1:2?
right.
To determine the ratio of C atoms to H atoms in the compound Ge[S(CH2)4CH3]4, you need to count the number of carbon (C) and hydrogen (H) atoms in the molecule.
a) The ratio of C atoms to H atoms can be found by counting the number of each atom and expressing it as the simplest whole number ratio.
In this compound, there are 4 carbon atoms (C) and 16 hydrogen atoms (H). To find the simplest ratio, you can divide both numbers by the greatest common divisor (GCD) of 4 and 16, which is 4.
So, the ratio of C atoms to H atoms in Ge[S(CH2)4CH3]4 is 1:4.
b) To determine the ratio of Ge to S by mass, you need to calculate the molar mass of both germanium (Ge) and sulfur (S) and then divide the molar mass of Ge by the molar mass of S.
The molar mass of Ge is 72.64 g/mol, while the molar mass of S is 32.06 g/mol.
The ratio of Ge to S by mass is calculated as follows:
Ratio = (Molar mass of Ge) / (Molar mass of S)
= 72.64 g/mol / 32.06 g/mol
≈ 2.27
Therefore, the ratio of Ge to S by mass in Ge[S(CH2)4CH3]4 is approximately 2.27:1.
Remember, to find such ratios, you need to know the chemical formula and have accurate molar masses of the elements involved.