write an expression that represents the width of a rectangle with length x+5 anmd area x to the 3 power + 12x to the 2nd power+ 47x+60
Divide the area by the length.
width = (x^3 + 12x^2 +47x +60)/(x + 5)
That ratio can be simplified by factoring x+5 out of the numerator, and cancelling it with the deominator.
You will be left with x^2 + 7x + 12
for the length.
To find the width of a rectangle, we need to use the formula for the area of a rectangle:
Area = length * width
Given that the length of the rectangle is x + 5 and the area is given by the expression x^3 + 12x^2 + 47x + 60, we can substitute these values into the formula and solve for width.
Area = (x + 5) * width
x^3 + 12x^2 + 47x + 60 = (x + 5) * width
Now, we need to isolate the variable "width" on one side of the equation. We can do this by dividing both sides of the equation by (x + 5):
(x^3 + 12x^2 + 47x + 60) / (x + 5) = width
Therefore, the expression that represents the width of the rectangle is:
width = (x^3 + 12x^2 + 47x + 60) / (x + 5)
To represent the width of a rectangle with length (x+5) and area (x^3 + 12x^2 + 47x + 60), you can use the formula for the area of a rectangle:
Area = Length × Width
Given that the length is (x+5) and the area is (x^3 + 12x^2 + 47x + 60), we can set up the equation as:
(x^3 + 12x^2 + 47x + 60) = (x+5) × Width
To find the width, we can solve for Width by dividing both sides of the equation by (x+5):
Width = (x^3 + 12x^2 + 47x + 60) / (x+5)
Therefore, the expression that represents the width of the rectangle is:
Width = (x^3 + 12x^2 + 47x + 60) / (x+5)