check this please

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  1. oh my

    (y^2 - 4y + 3)/(y^2 - 9) * (4y + 12)/(y^2 - 2y + 1)
    = (y-3)(y-1)/[(y+3)(y-3)] * 4(y+3)/[(y-1)(y-1)]
    = 4/(y-1) y ≠ ±1, ±3

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