i don't get this question

consecutive integers are integers that differ by one. you can represent consecutive integers as x,x+1,x+2 and so on. write an equation and solve to find 3 consecutive integers whose sum is 33

can you solve

x + x+1 + x+2 = 33 ?

no

http://www.jiskha.com/display.cgi?id=1274744758

I think Ms Sue solved this same equation for you in the post up the line

33/3=11. Since 11 is the average you have to go down by 1 (11-1) which equals 10. Then one up from 11 (11+1=12) so the answers are 10,11,12. Hope this helps

To solve this problem, we need to set up an equation and solve it to find the three consecutive integers whose sum is 33.

Let's represent the first consecutive integer as x. According to the problem, the next consecutive integer would be x + 1, and the one after that would be x + 2.

The sum of these three consecutive integers can be represented as:

x + (x + 1) + (x + 2) = 33

Now, let's solve this equation for x.

Combining like terms:

3x + 3 = 33

Subtracting 3 from both sides:

3x = 30

Dividing both sides by 3:

x = 10

So, the first consecutive integer is 10.

The next consecutive integer would be x + 1:

10 + 1 = 11

And the third consecutive integer would be x + 2:

10 + 2 = 12

Therefore, the three consecutive integers whose sum is 33 are 10, 11, and 12.