Balance the following equations:
a. C + O2 CO
b. CO + O2 CO2
c. H2 + Br2 HBr
d. K + H2O KOH + H2
e. Mg + O2 MgO
please explain and show work.
I will do two:
CO + O2>> CO2
2CO+O2>> 2CO2
K+ H2O>> KOH + H2
I find it helpful to write H2O as HOH
K+HOH>>KOH + H2
2K + 2HOH>> 2KOH + H2
then rewrite HOH as H2O
1:0.904 S/Cl
Sure! I'll walk you through each equation and show you how to balance them.
a. C + O2 -> CO
To balance this equation, we need to make sure that the number of each type of atom is the same on both sides.
On the left side, we have 1 carbon (C) atom and 2 oxygen (O) atoms. On the right side, we have 1 carbon (C) atom and 1 oxygen (O) atom.
To balance the equation, we need to add a coefficient in front of CO on the right side, so that it becomes CO2. Now the equation is balanced:
C + O2 -> CO2
b. CO + O2 -> CO2
Similar to the previous equation, we want to balance the number of each type of atom on both sides.
On the left side, we have 1 carbon (C) atom, 1 oxygen (O) atom, and 2 oxygen (O) atoms. On the right side, we have 1 carbon (C) atom and 2 oxygen (O) atoms.
To balance the equation, we need to add a coefficient in front of CO, so that it becomes 2CO. Now the equation is balanced:
2CO + O2 -> 2CO2
c. H2 + Br2 -> HBr
On the left side, we have 2 hydrogen (H) atoms and 2 bromine (Br) atoms. On the right side, we have 2 hydrogen (H) atoms and 2 bromine (Br) atoms.
The equation is already balanced.
H2 + Br2 -> HBr
d. K + H2O -> KOH + H2
On the left side, we have 1 potassium (K) atom, 1 hydrogen (H) atom, and 1 oxygen (O) atom. On the right side, we have 1 potassium (K) atom, 1 oxygen (O) atom, 1 hydrogen (H) atom, and 1 hydrogen (H) atom.
To balance the equation, we need to add a coefficient in front of H2O, so that it becomes 2H2O. Now the equation is balanced:
2K + 2H2O -> 2KOH + H2
e. Mg + O2 -> MgO
On the left side, we have 1 magnesium (Mg) atom and 2 oxygen (O) atoms. On the right side, we have 1 magnesium (Mg) atom and 1 oxygen (O) atom.
To balance the equation, we need to add a coefficient in front of MgO, so that it becomes 2MgO. Now the equation is balanced:
2Mg + O2 -> 2MgO