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Use the discriminant to determine how many real number solutions the equation has.

t^2 + 8t + 16 = 0

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Don

  1. discriminant= b2-4ac
    (8)^2-4(1)(16)
    64-64=0
    One real root (because it equals 0).
    If it was a positive number, there would be two real roots. If it was a negative number, there would be two COMPLEX roots.

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    Anonymous

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