If the mole fraction of sulfuric acid (H2SO4) in an aqueous solution is 0.325, wat is the percent by mass of H2SO4?

To find the percent by mass of H2SO4 in an aqueous solution, you need to follow a few steps:

Step 1: Determine the molar mass of H2SO4.
The molar mass of H2SO4 can be calculated by adding the individual atomic masses of its constituent elements: hydrogen (H), sulfur (S), and oxygen (O).

H2SO4:
2(1.01 g/mol) + 32.07 g/mol + 4(16.00 g/mol) = 98.09 g/mol

Step 2: Calculate the mass of H2SO4 in the solution.
To do this, you'll need to know the total mass of the solution or the volume and density of the solution. Since we don't have this information in the question, let's assume we have 100 grams of the solution for simplicity.

Mass of H2SO4 = Mole fraction of H2SO4 × Total mass of the solution
Mass of H2SO4 = 0.325 × 100 g = 32.5 g

Step 3: Calculate the percent by mass of H2SO4.
Percent by mass is the mass of the solute (H2SO4) divided by the total mass of the solution, multiplied by 100.

Percent by mass of H2SO4 = (Mass of H2SO4 ÷ Total mass of the solution) × 100
Percent by mass of H2SO4 = (32.5 g ÷ 100 g) × 100 = 32.5%

Therefore, the percent by mass of H2SO4 in the aqueous solution is 32.5%.