Which of the following is equivalent to the expression (t2 − t − 6)(t − 3)−1 ?
a. t3 − 9t +18
b. (t − 2)(t + 3)
c. (t + 2)(t − 3)
d. (t − 2)
e. (t + 2)this is the answer how is the problem worked out?
If t +2 is the answer, you have typed the question wrong. It should be
(t^2 − t − 6)*(t − 3)^-1
You omitted the ^ for the exponents. The t-3 can be cancelled out after factoring (t^2 − t − 6).
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Which of the following ia equivalent to the expression (t^2-t-6)(t-3)^-1?
a. t^3-9t+18
b. (t-2)(t+3)
c. (t+2)(t-3)
d. (t-2)
e. (t+2)
The correct answer is e, however, I cannot figure out how to work the problem out to get that answer. Can you show me how to work this out correctly?
14ex+4e−4=15
To find which expression is equivalent to the given expression, we need to simplify it.
The given expression is (t^2 − t − 6)(t − 3)^-1.
To simplify this expression, let's start with the term (t − 3)^-1. The exponent -1 means we are taking the reciprocal of the term t - 3, so we have 1/(t - 3).
Next, we need to multiply this by the expression (t^2 − t − 6).
Multiplying the two expressions, we get (t^2 − t − 6)/(t - 3).
Now, let's simplify the numerator by factoring the expression t^2 − t − 6. By factoring, we find that this expression can be written as (t - 3)(t + 2).
Therefore, our simplified expression is [(t - 3)(t + 2)]/(t - 3).
Now, we can cancel out the common factor (t - 3) in the numerator and denominator, leaving us with t + 2.
So the answer is (t + 2), which is option e.
Therefore, the correct answer is e. (t + 2).